x^2-200x+4950=0

Solution for x^2-200x+4950=0 equation:

x^2-200x+4950=0

a = 1; b = -200; c = +4950;
Δ = b2-4ac
Δ = -2002-4·1·4950
Δ = 20200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20200}=\sqrt{100*202}=\sqrt{100}*\sqrt{202}=10\sqrt{202}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-10\sqrt{202}}{2*1}=\frac{200-10\sqrt{202}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+10\sqrt{202}}{2*1}=\frac{200+10\sqrt{202}}{2}
$